Question

Solve the following equation: 4x² + 4 bx - (a² - b²) = 0

Answer 1

4x² + 4 bx - (a² - b²) = 0

`"x"^2 + "bx" - (("a"^2 - "b"^2))/4 = 0`

`"x"^2 + ("a + b")/2 xx -("a - b")/2 xx -("a"^2 - "b"^2)/4 = 0` 

`"x" {"x" + ("a + b")/2} - "(a - b)"/2 {"x" + ("a + b")/2} = 0`

`{"x" + (("a + b"))/2} {"x" - (("a - b"))/2} = 0`

`{"x" + (("a + b"))/2} = 0 , {"x" - (("a - b"))/2} = 0`

`"x" = -(("a + b"))/2 , "x" = (("a - b"))/2`