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प्रश्न
Solve the following equation: `"x"^2 - ( sqrt 2 + 1) "x" + sqrt 2 = 0 `
योग
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उत्तर
`"x"^2 - ( sqrt 2 + 1) "x" + sqrt 2 = 0 `
`"x"^2 - "x" - sqrt 2 "x" + sqrt 2 = 0`
`"x"("x" - 1) - sqrt 2 ("x" - 1) = 0`
(x - 1) `("x" - sqrt 2) = 0`
(x - 1) = 0 , `(x - sqrt 2)` = 0
x = 1 , x = `sqrt 2`
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