Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
x (2x + 1) = 6
Advertisements
उत्तर
x (2x + 1) = 6
2x2 + x - 6 = 0
2x2 + 4x - 3x - 6 = 0
⇒ 2x (x + 2) - 3 (x + 2) = 0
⇒ (x + 2) (2x - 3) = 0
Either x + 2 = 0,
then x = -2
or
2x - 3 = 0,
then 2x = 3
⇒ x = `(3)/(2)`
Hence x = `-2, (3)/(2)`.
APPEARS IN
संबंधित प्रश्न
An aeroplane left 50 minutes later than its scheduled time, and in order to reach the destination, 1250 km away, in time, it had to increase its speed by 250 km/hr from its usual speed. Find its usual speed.
For the equation given below, find the value of ‘m’ so that the equation has equal roots. Also, find the solution of the equation:
x2 – (m + 2)x + (m + 5) = 0
One of the roots of equation 5m2 + 2m + k = 0 is `(-7)/5` Complete the following activity to find the value of 'k'.
Solve the following equation: 2x2 - x - 6 = 0
Solve the following equation: c
Solve the following equation :
`1/(("x" - 1)(x - 2)) + 1/(("x" - 2)("x" - 3)) + 1/(("x" - 3)("x" -4)) = 1/6`
An aeroplane travelled a distance of 400 km at an average speed of x km/hr. On the return journey the speed was increased by 40 km/hr. Write down the expression for the time taken for
The outward journey
Solve the following equation by factorization
`4sqrt(3)x^2 + 5x - 2sqrt(3)` = 0
The speed of a boat in still water is 11 km/ hr. It can go 12 km up-stream and return downstream to the original point in 2 hours 45 minutes. Find the speed of the stream
The product of two successive integral multiples of 5 is 300. Then the numbers are:
