Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
(x – 3) (2x + 5) = 0
Advertisements
उत्तर
(x – 3) (2x + 5) = 0
Either x – 3 = 0,
Then x = 3
or
2x + 5 = 0 then 2x = -5
⇒ x = `(-5)/(2)`
Hence x = 3, = `(-5)/(2)`.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation for x:
`x^2+(a/(a+b)+(a+b)/a)x+1=0`
Solve (i) x2 + 3x – 18 = 0
(ii) (x – 4) (5x + 2) = 0
(iii) 2x2 + ax – a2 = 0; where ‘a’ is a real number
There are three consecutive integers such that the square of the first increased by the product of the first increased by the product of the others the two gives 154. What are the integers?
Solve the given quadratic equation for x : 9x2 – 9(a + b)x + (2a2 + 5ab + 2b2) = 0 ?
Solve the following quadratic equation by factorisation.
2m (m − 24) = 50
Solve the following quadratic equations by factorization:
\[2x^2 + ax - a^2 = 0\]
The difference of the square of two natural numbers is 45. The square of the smaller number is 4 times the larger number. Determine the numbers.
Solve equation using factorisation method:
(x + 3)2 – 4(x + 3) – 5 = 0
Solve the following quadratic equation by factorisation:
x2 + 3x - 18 = 0
If α and β are roots of the quadratic equation x2 – 7x + 10 = 0, find the quadratic equation whose roots are α2 and β2.
