Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by factorisation:
x2 + 3x - 18 = 0
Advertisements
उत्तर
The given quadratic equation is
x2 + 3x - 18 = 0
⇒ x2 + 6x - 3x - 18 = 0
⇒ x(x + 6) -3(x + 6) = 0
⇒ (x + 6) (x - 3) = 0
when x + 6 = 0
x = -6
when x - 3 = 0
x = 3
∴ x = {-6, 3}.
संबंधित प्रश्न
Solve the equation `4/x-3=5/(2x+3); xne0,-3/2` for x .
Solve for x :
`2/(x+1)+3/(2(x-2))=23/(5x), x!=0,-1,2`
Solve the following quadratic equations by factorization:
a2x2 - 3abx + 2b2 = 0
Find the two consecutive natural numbers whose product is 20.
Find the value of k for which the following equations have real and equal roots:
\[x^2 + k\left( 2x + k - 1 \right) + 2 = 0\]
Write the condition to be satisfied for which equations ax2 + 2bx + c = 0 and \[b x^2 - 2\sqrt{ac}x + b = 0\] have equal roots.
If \[x = - \frac{1}{2}\],is a solution of the quadratic equation \[3 x^2 + 2kx - 3 = 0\] ,find the value of k.
If sin α and cos α are the roots of the equations ax2 + bx + c = 0, then b2 =
Solve the following equation: a2x2 - 3abx + 2b2 = 0
A two digit positive number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places. Find the number.
