Advertisements
Advertisements
प्रश्न
In each of the following determine whether the given values are solutions of the equation or not.
x2 + x + 1 = 0; x = 1, x = -1.
Advertisements
उत्तर
Given equation is
x2 + x + 1 = 0; x = 1, x = -1
Substitute x = 1 in L.H.S.
L.H.S. = (1)2 + (1) + 1
= 3 ≠ R.H.S. ≠ 0
Hence, x = 1 is not a solution of the given equation.
Now substitute x = -1 in L.H.S.
L.H.S. = (-1)2 + (-1) + 1
= 1 - 1 + 1
= 1 ≠ R.H.S. ≠ 0
Hence, x = -1 is not a solution of the given equation.
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`10x-1/x=3`
Solve the following quadratic equations by factorization:
a2x2 - 3abx + 2b2 = 0
`x^2-4x+1=0`
Solve the following quadratic equations by factorization: \[\sqrt{3} x^2 - 2\sqrt{2}x - 2\sqrt{3} = 0\]
The value of c for which the equation ax2 + 2bx + c = 0 has equal roots is
The perimeter of the right angled triangle is 60cm. Its hypotenuse is 25cm. Find the area of the triangle.
A farmer wishes to grow a 100m2 rectangular vegetable garden. Since he was with him only 30m barbed wire, he fences 3 sides of the rectangular garden letting the compound of his house to act as the 4th side. Find the dimensions of his garden .
In each of the following determine whether the given values are solutions of the equation or not
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
The lengths of the parallel sides of a trapezium are (x + 9) cm and (2x – 3) cm and the distance between them is (x + 4) cm. If its area is 540 cm2, find x.
