Advertisements
Advertisements
Question
Solve the following equation by factorization
x (2x + 1) = 6
Advertisements
Solution
x (2x + 1) = 6
2x2 + x - 6 = 0
2x2 + 4x - 3x - 6 = 0
⇒ 2x (x + 2) - 3 (x + 2) = 0
⇒ (x + 2) (2x - 3) = 0
Either x + 2 = 0,
then x = -2
or
2x - 3 = 0,
then 2x = 3
⇒ x = `(3)/(2)`
Hence x = `-2, (3)/(2)`.
APPEARS IN
RELATED QUESTIONS
`2x^2+5x-3=0`
Solve the following equation: 4x2 - 13x - 12 = 0
Solve the following equation :
`1/(("x" - 1)(x - 2)) + 1/(("x" - 2)("x" - 3)) + 1/(("x" - 3)("x" -4)) = 1/6`
A two digit number is four times the sum and 3 times the product of its digits, find the number.
Solve equation using factorisation method:
2(x2 – 6) = 3(x – 4)
Solve equation using factorisation method:
`5/("x" -2) - 3/("x" + 6) = 4/"x"`
Find two consecutive positive even integers whose squares have the sum 340.
In each of the following determine whether the given values are solutions of the equation or not
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Solve the following equation by factorization
4x2 = 3x
Solve the following equation by factorisation :
`sqrt(x + 15) = x + 3`
