English
Maharashtra State BoardSSC (English Medium) 10th Standard

Solve the following quadratic equation by factorisation. 2x2+7x+52=0 to solve this quadratic equation by factorisation, complete the following activity. - Algebra Mathematics 1

Advertisements
Advertisements

Question

Solve the following quadratic equation by factorisation.

`sqrt2 x^2 + 7x + 5sqrt2 = 0`  to solve this quadratic equation by factorisation, complete the following activity.

`sqrt2 x^2 + 7x + 5sqrt2 = 0`

`sqrt2x^2+square+square+5sqrt2=0` 

`x("______") + sqrt2 ("______") = 0`

`("______") (x + sqrt2) = 0`

`("______") = 0 or (x + sqrt2) = 0`

∴ x = `square or x = -sqrt2`

 `square` and `-sqrt(2)` are roots of the equation.

Fill in the Blanks
Sum
Advertisements

Solution

`sqrt2 x^2 + 7x + 5sqrt2 = 0`

`sqrt2x^2+bb(5x)+bb(2x)+5sqrt2=0` 

`xbb((sqrt2x+5)) + sqrt2 bb((sqrt2x+5)) = 0`

`bb((sqrt2x+5)) (x + sqrt2) = 0`

`bb((sqrt2x+5)) = 0 or (x + sqrt2) = 0`

∴ x = `bb((-5)/sqrt2) or x = -sqrt2`

 `bb((-5)/sqrt2)` and `-sqrt(2)` are roots of the equation.

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Quadratic Equations - Practice Set 2.2 [Page 36]

APPEARS IN

Balbharati Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
Chapter 2 Quadratic Equations
Practice Set 2.2 | Q 1.07 | Page 36
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×