हिंदी

Solve the following quadratic equation by factorisation. 2x2+7x+52=0 to solve this quadratic equation by factorisation, complete the following activity. - Algebra

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प्रश्न

Solve the following quadratic equation by factorisation.

`sqrt2 x^2 + 7x + 5sqrt2 = 0`  to solve this quadratic equation by factorisation, complete the following activity.

`sqrt2 x^2 + 7x + 5sqrt2 = 0`

`sqrt2x^2+square+square+5sqrt2=0` 

`x("______") + sqrt2 ("______") = 0`

`("______") (x + sqrt2) = 0`

`("______") = 0 or (x + sqrt2) = 0`

∴ x = `square or x = -sqrt2`

 `square` and `-sqrt(2)` are roots of the equation.

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योग
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उत्तर

`sqrt2 x^2 + 7x + 5sqrt2 = 0`

`sqrt2x^2+bb(5x)+bb(2x)+5sqrt2=0` 

`xbb((sqrt2x+5)) + sqrt2 bb((sqrt2x+5)) = 0`

`bb((sqrt2x+5)) (x + sqrt2) = 0`

`bb((sqrt2x+5)) = 0 or (x + sqrt2) = 0`

∴ x = `bb((-5)/sqrt2) or x = -sqrt2`

 `bb((-5)/sqrt2)` and `-sqrt(2)` are roots of the equation.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Quadratic Equations - Practice Set 2.2 [पृष्ठ ३६]

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बालभारती Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
अध्याय 2 Quadratic Equations
Practice Set 2.2 | Q 1.07 | पृष्ठ ३६
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