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Question
`(1 + cot^2A)/(1 + tan^2A)` = ?
Options
tan2A
sec2A
cosec2A
cot2A
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Solution
cot2A
Explanation:
`(1 + cot^2A)/(1 + tan^2A)`
= `("cosec"^2A)/(sec^2A)`
= `(1/(sin^2A))/(1/(cos^2A))`
= `(cos^2A)/(sin^2A)`
= cot2A
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Solution :
L.H.S. = cotθ + tanθ
= `cosθ/sinθ + sinθ/cosθ`
= `(square + square)/(sinθ xx cosθ)`
= `1/(sinθ xx cosθ)` ............... `square`
= `1/sinθ xx 1/square`
= cosecθ × secθ
L.H.S. = R.H.S
∴ cotθ + tanθ = cosecθ × secθ
If tan θ = `x/y`, then cos θ is equal to ______.
