English
Maharashtra State BoardSSC (English Medium) 10th Standard

Sin ⁡θ = 1/2, then θ = ? A) 30° B) 45° C) 60° D) 90°

Advertisements
Advertisements

Question

`sin θ = 1/2`, then θ = ?

Options

  • 30°

  • 45°

  • 60°

  • 90°

MCQ
Advertisements

Solution

30°

Explanation:

`sin θ = 1/2`

∴ θ = 30°   ...`[sin 30^circ = 1/2]`

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Trigonometry - Exercise

RELATED QUESTIONS

Evaluate without using trigonometric tables:

`cos^2 26^@ + cos 64^@ sin 26^@ + (tan 36^@)/(cot 54^@)`


Prove that `(tan^2 theta)/(sec theta - 1)^2 = (1 + cos theta)/(1 - cos theta)`


Prove the following trigonometric identities.

`sqrt((1 - cos A)/(1 + cos A)) = cosec A - cot A`


Prove the following identities:

(cos A + sin A)2 + (cos A – sin A)2 = 2


Prove the following identities:

`cosA/(1 + sinA) + tanA = secA`


`(1-tan^2 theta)/(cot^2-1) = tan^2 theta`


Write the value of `(sin^2 theta 1/(1+tan^2 theta))`. 


Prove that:

Sin4θ - cos4θ = 1 - 2cos2θ


If \[\cos A = \frac{7}{25}\]  find the value of tan A + cot A. 


Prove the following identity :

`cosec^4A - cosec^2A = cot^4A + cot^2A`


Prove the following identity :

`(cotA + tanB)/(cotB + tanA) = cotAtanB`


Prove the following identity :

`(sec^2θ - sin^2θ)/tan^2θ = cosec^2θ - cos^2θ`


Without using trigonometric table , evaluate : 

`cosec49°cos41° + (tan31°)/(cot59°)`


Prove that cot θ. tan (90° - θ) - sec (90° - θ). cosec θ + 1 = 0.


Prove the following identities.

sec4 θ (1 – sin4 θ) – 2 tan2 θ = 1


If x sin3 θ + y cos3 θ = sin θ cos θ and x sin θ = y cos θ, then prove that x2 + y2 = 1


If tan θ + cot θ = 2, then tan2θ + cot2θ = ?


If `sec θ = 41/40`, then find values of sin θ, cot θ, cosec θ.


Show that tan4θ + tan2θ = sec4θ – sec2θ.


Complete the following activity to prove:

cotθ + tanθ = cosecθ × secθ

Activity: L.H.S. = cotθ + tanθ

= `cosθ/sinθ + square/cosθ`

= `(square + sin^2theta)/(sinθ xx cosθ)`

= `1/(sinθ xx  cosθ)` ....... ∵ `square`

= `1/sinθ xx 1/cosθ`

= `square xx secθ`

∴ L.H.S. = R.H.S.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×