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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Which is the most suitable reagent for the following conversion? ....................O.....................................O.....................||......................................||.CHX3−CH= - Chemistry

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प्रश्न

Which is the most suitable reagent for the following conversion?

\[\begin{array}{cc}
\phantom{....................}\ce{O}\phantom{.....................................}\ce{O}\phantom{.}\\
\phantom{....................}||\phantom{......................................}||\phantom{.}\\
\phantom{}\ce{CH3 - CH = CH - CH2 - C - CH3 -> CH3 - CH = CH - CH2 - C - OH}\phantom{.}
\end{array}\]

पर्याय

  • Tollen’s reagent

  • Benzoyl peroxide

  • \[\ce{I2}\] and \[\ce{NaOH}\] solution

  • \[\ce{Sn}\] and \[\ce{NaOH}\] solution

MCQ
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उत्तर

\[\ce{I2}\] and \[\ce{NaOH}\] solution

Explanation:

\[\begin{array}{cc}
\phantom{......................}\ce{O}\phantom{....................................}\ce{O}\phantom{..............}\\
\phantom{....................}||\phantom{.....................................}||\phantom{............}\\
\phantom{}\ce{CH3CH = CH - CH2 - C - CH3 ->[I2 + NaOH] CH3CH = CHCH2 - C - ONa + CHI3}\\
\phantom{............................................}\ce{↓ H2O}\\
\phantom{.......................................................}\ce{O}\\
\phantom{.......................................................}||\\
\phantom{.........................................}\ce{CH3CH = CHCH2 - C - OH}
\end{array}\]

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पाठ 12: Aldehydes, Ketones and Carboxylic Acids - Multiple Choice Questions (Type - I) [पृष्ठ १७०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 12 Aldehydes, Ketones and Carboxylic Acids
Multiple Choice Questions (Type - I) | Q 10 | पृष्ठ १७०

संबंधित प्रश्‍न

Identify ‘A' and ‘B’ in the following reaction :

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(Reactions)
Column II
(Reagents)
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(b)
\[\begin{array}{cc}
\ce{O}\phantom{.................}\\
||\phantom{.................}\\
\ce{R - C - CH3 + NaOX ->}
\end{array}\]
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Choose the correct answer from the options given below.


Y is:


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