मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Show how the following compound can be converted to benzoic acid. Bromobenzene

Advertisements
Advertisements

प्रश्न

Show how the following compound can be converted to benzoic acid.

Bromobenzene

रासायनिक समीकरणे/रचना
Advertisements

उत्तर

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Aldehydes, Ketones and Carboxylic Acids - Intext Questions [पृष्ठ २४८]

APPEARS IN

एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 8 Aldehydes, Ketones and Carboxylic Acids
Intext Questions | Q 8.7 (iii) | पृष्ठ २४८

संबंधित प्रश्‍न

Predict the products of the following reactions:


Show how the following compound can be converted to benzoic acid.

Acetophenone


Predict the products formed when cyclohexanecarbaldehyde reacts with the following reagent.

Tollens’ reagent


An organic compound (A) (molecular formula C8H16O2) was hydrolysed with dilute sulphuric acid to give a carboxylic acid (B) and an alcohol (C). Oxidation of (C) with chromic acid produced (B). (C) on dehydration gives but-1-ene. Write equations for the reactions involved.


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

Methyl benzoate


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

m-Nitrobenzoic acid


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

p-Nitrobenzoic acid


How will you bring about the following conversion in not more than two steps?

Benazaldehyde to α-Hydroxyphenylacetic acid


How is methoxy benzene prepared from carbolic acid?


Name the reagents used in the following reactions:


What is the action of following reagents on glucose?
1. Bromine water
2. Hydroxylamine


The functional group present in triacylglycerol is _______.


The reagent which does not react with both, acetone and benzaldehyde.


Which is the most suitable reagent for the following conversion?

\[\begin{array}{cc}
\phantom{....................}\ce{O}\phantom{.....................................}\ce{O}\phantom{.}\\
\phantom{....................}||\phantom{......................................}||\phantom{.}\\
\phantom{}\ce{CH3 - CH = CH - CH2 - C - CH3 -> CH3 - CH = CH - CH2 - C - OH}\phantom{.}
\end{array}\]


Match the reactions given in Column I with the suitable reagents given in Column II.

Column I
(Reactions)
Column II
(Reagents)
(i) Benzophenone Diphenylmethane (a) \[\ce{LiAlH4}\]
(ii) Benzaldehyde 1-Phenylethanol (b) \[\ce{DIBAL-H}\]
(iii) Cyclohexanone Cyclohexanol (c) \[\ce{Zn(Hg)/Conc. HCl}\]
(iv) Phenyl benzoate Benzaldehyde (d) \[\ce{CH3MgBr}\]

Assertion: Aldehydes and ketones, both react with Tollen’s reagent to form silver mirror.

Reason: Both, aldehydes and ketones contain a carbonyl group.


Benzoic acid can be obtained by the oxidation of all of the following EXCEPT ______.


Y is:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×