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प्रश्न
Show how the following compound can be converted to benzoic acid.
Acetophenone
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उत्तर

APPEARS IN
संबंधित प्रश्न
On acid hydrolysis, propane nitrile gives.
How is carbolic acid prepared from chlorobenzene?
Identify ‘A' and ‘B’ in the following reaction :
C6H5MgBr + C02 `(`> ‘A’ `(PCl_5)/()`> ‘B’
Predict the products of the following reactions:

Name the reagents used in the following reactions:

Show how the following compound can be converted to benzoic acid.
Ethylbenzene
Show how the following compound can be converted to benzoic acid.
Bromobenzene
Show how the following compound can be converted to benzoic acid.
Phenylethene (Styrene)
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
Methyl benzoate
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
m-Nitrobenzoic acid
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
p-Nitrobenzoic acid
Complete the synthesis by giving missing starting material, reagent or product.

Through which of the following reactions number of carbon atoms can be increased in the chain?
(i) Grignard reaction
(ii) Cannizaro’s reaction
(iii) Aldol condensation
(iv) HVZ reaction
Substitution of one alkyl group by replacing hydrogen of primary amines
Match List - I with List - II.
| List - I | List - II | ||
| (a) | \[\ce{->[CO,HCl][Anhyd. AlCl3/CuCl]}\] |
(i) | Hell-Volhard-Zelinsky reaction |
| (b) |
\[\begin{array}{cc}
\ce{O}\phantom{.................}\\ ||\phantom{.................}\\ \ce{R - C - CH3 + NaOX ->} \end{array}\] |
(ii) | Gattermann-Koch reaction |
| (c) | \[\ce{R - CH2 - OH + R'COOH ->[Conc. H2SO4]}\] | (iii) | Haloform reaction |
| (d) | \[\ce{R - CH2COOH ->[(i) X2/Red P][(ii) H2O]}\] | (iv) | Esterification |
Choose the correct answer from the options given below.
The end product Y in the sequence of reaction:
\[\ce{RX ->[CN^-] X ->[NaOH] Y}\] is:

Y is:
Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C. The compound 'C' is ______.
\[\ce{->[CO,HCl][Anhyd. AlCl3/CuCl]}\]