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प्रश्न
Identify ‘A' and ‘B’ in the following reaction :
C6H5MgBr + C02 `(`> ‘A’ `(PCl_5)/()`> ‘B’
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उत्तर
C6H5MgBr + CO2`"Dry ether"/("H"^+ /(H_2O))`> C6H5COOH `"PCl"/`> C6H5COCl
Phenyl Benzoic acid Benzoyl magnesium (A) chloride bromide (B)
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\[\begin{array}{cc}
\phantom{....................}\ce{O}\phantom{.....................................}\ce{O}\phantom{.}\\
\phantom{....................}||\phantom{......................................}||\phantom{.}\\
\phantom{}\ce{CH3 - CH = CH - CH2 - C - CH3 -> CH3 - CH = CH - CH2 - C - OH}\phantom{.}
\end{array}\]
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| Column I (Reactions) |
Column II (Reagents) |
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| (ii) Benzaldehyde 1-Phenylethanol | (b) \[\ce{DIBAL-H}\] |
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| List - I | List - II | ||
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| (b) |
\[\begin{array}{cc}
\ce{O}\phantom{.................}\\ ||\phantom{.................}\\ \ce{R - C - CH3 + NaOX ->} \end{array}\] |
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