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प्रश्न
Show how the following compound can be converted to benzoic acid.
Bromobenzene
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उत्तर
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संबंधित प्रश्न
On acid hydrolysis, propane nitrile gives.
How is carbolic acid prepared from chlorobenzene?
Write the structures of A and B in the following reactions
Predict the products of the following reactions:
Name the reagents used in the following reactions:
Show how the following compound can be converted to benzoic acid.
Ethylbenzene
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
Methyl benzoate
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
p-Nitrobenzoic acid
Complete the synthesis by giving missing starting material, reagent or product.
Name the reagents used in the following reactions:
What is the action of following reagents on glucose?
1. Bromine water
2. Hydroxylamine
The reagent which does not react with both, acetone and benzaldehyde.
Match the reactions given in Column I with the suitable reagents given in Column II.
| Column I (Reactions) |
Column II (Reagents) |
| (i) Benzophenone Diphenylmethane | (a) \[\ce{LiAlH4}\] |
| (ii) Benzaldehyde 1-Phenylethanol | (b) \[\ce{DIBAL-H}\] |
| (iii) Cyclohexanone Cyclohexanol | (c) \[\ce{Zn(Hg)/Conc. HCl}\] |
| (iv) Phenyl benzoate Benzaldehyde | (d) \[\ce{CH3MgBr}\] |
Assertion: Aldehydes and ketones, both react with Tollen’s reagent to form silver mirror.
Reason: Both, aldehydes and ketones contain a carbonyl group.
Substitution of one alkyl group by replacing hydrogen of primary amines
Benzoic acid can be obtained by the oxidation of all of the following EXCEPT ______.
Match List - I with List - II.
| List - I | List - II | ||
| (a) |  \[\ce{->[CO,HCl][Anhyd. AlCl3/CuCl]}\] |
(i) | Hell-Volhard-Zelinsky reaction |
| (b) |
\[\begin{array}{cc}
\ce{O}\phantom{.................}\\ ||\phantom{.................}\\ \ce{R - C - CH3 + NaOX ->} \end{array}\] |
(ii) | Gattermann-Koch reaction |
| (c) | \[\ce{R - CH2 - OH + R'COOH ->[Conc. H2SO4]}\] | (iii) | Haloform reaction |
| (d) | \[\ce{R - CH2COOH ->[(i) X2/Red P][(ii) H2O]}\] | (iv) | Esterification |
Choose the correct answer from the options given below.
A compound 'X' with molecular formula C3H8O can be oxidised to a compound 'Y' with the molecular formula C3H6O2 'X' is most likely to be ______.
Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C. The compound 'C' is ______.
