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प्रश्न
How will you bring about the following conversion in not more than two steps?
Benazaldehyde to α-Hydroxyphenylacetic acid
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उत्तर १

उत्तर २

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संबंधित प्रश्न
How is carbolic acid prepared from chlorobenzene?
Identify ‘A' and ‘B’ in the following reaction :
C6H5MgBr + C02 `(`> ‘A’ `(PCl_5)/()`> ‘B’
Show how the following compound can be converted to benzoic acid.
Ethylbenzene
Show how the following compound can be converted to benzoic acid.
Bromobenzene
An organic compound (A) (molecular formula C8H16O2) was hydrolysed with dilute sulphuric acid to give a carboxylic acid (B) and an alcohol (C). Oxidation of (C) with chromic acid produced (B). (C) on dehydration gives but-1-ene. Write equations for the reactions involved.
How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.
Phenylacetic acid
What is the action of following reagents on glucose?
1. Bromine water
2. Hydroxylamine
Through which of the following reactions number of carbon atoms can be increased in the chain?
(i) Grignard reaction
(ii) Cannizaro’s reaction
(iii) Aldol condensation
(iv) HVZ reaction
Match the reactions given in Column I with the suitable reagents given in Column II.
| Column I (Reactions) |
Column II (Reagents) |
| (i) Benzophenone Diphenylmethane | (a) \[\ce{LiAlH4}\] |
| (ii) Benzaldehyde 1-Phenylethanol | (b) \[\ce{DIBAL-H}\] |
| (iii) Cyclohexanone Cyclohexanol | (c) \[\ce{Zn(Hg)/Conc. HCl}\] |
| (iv) Phenyl benzoate Benzaldehyde | (d) \[\ce{CH3MgBr}\] |
Assertion: Aldehydes and ketones, both react with Tollen’s reagent to form silver mirror.
Reason: Both, aldehydes and ketones contain a carbonyl group.
Substitution of one alkyl group by replacing hydrogen of primary amines
Benzoic acid can be obtained by the oxidation of all of the following EXCEPT ______.
Match List - I with List - II.
| List - I | List - II | ||
| (a) | \[\ce{->[CO,HCl][Anhyd. AlCl3/CuCl]}\] |
(i) | Hell-Volhard-Zelinsky reaction |
| (b) |
\[\begin{array}{cc}
\ce{O}\phantom{.................}\\ ||\phantom{.................}\\ \ce{R - C - CH3 + NaOX ->} \end{array}\] |
(ii) | Gattermann-Koch reaction |
| (c) | \[\ce{R - CH2 - OH + R'COOH ->[Conc. H2SO4]}\] | (iii) | Haloform reaction |
| (d) | \[\ce{R - CH2COOH ->[(i) X2/Red P][(ii) H2O]}\] | (iv) | Esterification |
Choose the correct answer from the options given below.
The end product Y in the sequence of reaction:
\[\ce{RX ->[CN^-] X ->[NaOH] Y}\] is:
A compound 'X' with molecular formula C3H8O can be oxidised to a compound 'Y' with the molecular formula C3H6O2 'X' is most likely to be ______.
Fill in the blanks by choosing the appropriate words from those given in the brackets:
[stable, low, aldehyde, unstable, 6, 4, ethane, Clemmensen’s, 2, 3, carboxylic acid, high, propane, Rosenmund's]
The primary alcohols are easily oxidised first into ______ and then into ______.
\[\ce{->[CO,HCl][Anhyd. AlCl3/CuCl]}\]