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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom. Phenylacetic acid - Chemistry

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प्रश्न

How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

Phenylacetic acid

रासायनिक समीकरण/संरचनाएँ
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उत्तर

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अध्याय 8: Aldehydes, Ketones and Carboxylic Acids - Exercises [पृष्ठ २५६]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 8 Aldehydes, Ketones and Carboxylic Acids
Exercises | Q 8.14 (iv) | पृष्ठ २५६

संबंधित प्रश्न

Predict the products of the following reactions:


Show how the following compound can be converted to benzoic acid.

Acetophenone


Predict the products formed when cyclohexanecarbaldehyde reacts with the following reagent.

Tollens’ reagent


An organic compound (A) (molecular formula C8H16O2) was hydrolysed with dilute sulphuric acid to give a carboxylic acid (B) and an alcohol (C). Oxidation of (C) with chromic acid produced (B). (C) on dehydration gives but-1-ene. Write equations for the reactions involved.


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

m-Nitrobenzoic acid


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

p-Nitrobenzoic acid


Complete the synthesis by giving missing starting material, reagent or product.


How is methoxy benzene prepared from carbolic acid?


Name the reagents used in the following reactions:


The functional group present in triacylglycerol is _______.


The reagent which does not react with both, acetone and benzaldehyde.


Which is the most suitable reagent for the following conversion?

\[\begin{array}{cc}
\phantom{....................}\ce{O}\phantom{.....................................}\ce{O}\phantom{.}\\
\phantom{....................}||\phantom{......................................}||\phantom{.}\\
\phantom{}\ce{CH3 - CH = CH - CH2 - C - CH3 -> CH3 - CH = CH - CH2 - C - OH}\phantom{.}
\end{array}\]


Assertion: Aldehydes and ketones, both react with Tollen’s reagent to form silver mirror.

Reason: Both, aldehydes and ketones contain a carbonyl group.


Which of the following substance produced acetaldehyde on dry distillation?


Match List - I with List - II.

List - I List - II
(a) \[\ce{->[CO,HCl][Anhyd. AlCl3/CuCl]}\] (i) Hell-Volhard-Zelinsky reaction
(b)
\[\begin{array}{cc}
\ce{O}\phantom{.................}\\
||\phantom{.................}\\
\ce{R - C - CH3 + NaOX ->}
\end{array}\]
(ii) Gattermann-Koch reaction
(c) \[\ce{R - CH2 - OH + R'COOH ->[Conc. H2SO4]}\] (iii) Haloform reaction
(d) \[\ce{R - CH2COOH ->[(i) X2/Red P][(ii) H2O]}\] (iv) Esterification

Choose the correct answer from the options given below.


Y is:


Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C. The compound 'C' is ______.


Fill in the blanks by choosing the appropriate words from those given in the brackets:

[stable, low, aldehyde, unstable, 6, 4, ethane, Clemmensen’s, 2, 3, carboxylic acid, high, propane, Rosenmund's]

The primary alcohols are easily oxidised first into ______ and then into ______.


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