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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom. Phenylacetic acid - Chemistry

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प्रश्न

How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

Phenylacetic acid

रासायनिक समीकरणे/रचना
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उत्तर

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पाठ 8: Aldehydes, Ketones and Carboxylic Acids - Exercises [पृष्ठ २५६]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 8 Aldehydes, Ketones and Carboxylic Acids
Exercises | Q 8.14 (iv) | पृष्ठ २५६

संबंधित प्रश्‍न

On acid hydrolysis, propane nitrile gives.


How is carbolic acid prepared from chlorobenzene?


Predict the products of the following reactions:


Name the reagents used in the following reactions:


An organic compound (A) (molecular formula C8H16O2) was hydrolysed with dilute sulphuric acid to give a carboxylic acid (B) and an alcohol (C). Oxidation of (C) with chromic acid produced (B). (C) on dehydration gives but-1-ene. Write equations for the reactions involved.


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

Methyl benzoate


How will you prepare the given compound from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom.

p-Nitrobenzoic acid


How will you bring about the following conversion in not more than two steps?

Benazaldehyde to α-Hydroxyphenylacetic acid


Name the reagents used in the following reactions:


What is the action of following reagents on glucose?
1. Bromine water
2. Hydroxylamine


The functional group present in triacylglycerol is _______.


Which is the most suitable reagent for the following conversion?

\[\begin{array}{cc}
\phantom{....................}\ce{O}\phantom{.....................................}\ce{O}\phantom{.}\\
\phantom{....................}||\phantom{......................................}||\phantom{.}\\
\phantom{}\ce{CH3 - CH = CH - CH2 - C - CH3 -> CH3 - CH = CH - CH2 - C - OH}\phantom{.}
\end{array}\]


Match the reactions given in Column I with the suitable reagents given in Column II.

Column I
(Reactions)
Column II
(Reagents)
(i) Benzophenone Diphenylmethane (a) \[\ce{LiAlH4}\]
(ii) Benzaldehyde 1-Phenylethanol (b) \[\ce{DIBAL-H}\]
(iii) Cyclohexanone Cyclohexanol (c) \[\ce{Zn(Hg)/Conc. HCl}\]
(iv) Phenyl benzoate Benzaldehyde (d) \[\ce{CH3MgBr}\]

Assertion: Aldehydes and ketones, both react with Tollen’s reagent to form silver mirror.

Reason: Both, aldehydes and ketones contain a carbonyl group.


Which of the following substance produced acetaldehyde on dry distillation?


The end product Y in the sequence of reaction:

\[\ce{RX ->[CN^-] X ->[NaOH] Y}\] is:


Y is:


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