Advertisements
Advertisements
प्रश्न
What are the factors that affect the frequency of a vibrating string and how do they affect the frequency?
Advertisements
उत्तर
The frequency (f) of a vibrating string is affected by:
(i) The length of the vibrating string. Frequency is inversely proportional to the length, i.e, `"f"α1/"l"`. it means, if length increases, frequency becomes less and if length decreases, frequency increases.
(ii) It is directly proportional to the square root of the tension, other factors remaining the same, e.g., if tension (or stretching force) is made 4 times, then the frequency will be `(sqrt4=2)` doubled.
(iii) The frequency, (f) is inversely proportional to the square root of the mass of unit length of the vibrating string, i.e., `"f"α1/sqrt"m′"` if m' is the mass of unit length of the string. Since m' = πr2.l, it shows that f is `α1/sqrt("r"^2)` or `1/"r"`, where r is the radius of the vibrating strings.
संबंधित प्रश्न
Distinguish between the free (or natural) and forced vibrations.
A vibrating tuning fork, held over an air column of a given length with its one end closed, produces a loud audible sound. Name the phenomenon responsible for it and explain the observation.
When a body vibrates under a periodic force, the vibrations of the body are ______.
A tuning fork of frequency 256 Hz will resonate with another tuning fork of frequency:
In fig. shows two tuning forks P and Q of the same frequency mounted on separate sound boxes with their open ends facing each other. The fork A is set into vibration. (i) Describe your observation. (ii) State the principle illustrated by this experiment.
Differentiate between the following:
Light and sound waves.
Differentiate between the following:
Free and forced vibrations.
What do you mean by resonance? When does resonance occur?
A string stretched between its ends is made to vibrate by placing the stem of a vibrating tuning fork at its one end. State three ways how you will increase the frequency of note produced by the string.
