मराठी

The Following Table Gives the Distribution of Iq'S (Intelligence Quotients) of 60 Pupils of Class V in a School: Draw a Frequency Polygon for the Above Data.

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प्रश्न

The following table gives the distribution of IQ's (intelligence quotients) of 60 pupils of class V in a school:

IQ's: 125.5
to
13.25
118.5
to
125.5
111.5
to
118.5
104.5
to
111.5
97.5
to
104.5
90.5
to
97.5
83.5
to
90.5
76.5
to
83.5
69.5
to
76.5
62.5
to
69.5
No.
of pupils:
1 3 4 6 10 12 15 5 3 1

Draw a frequency polygon for the above data.

थोडक्यात उत्तर
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उत्तर १

We first draw horizontal and vertical axes. Let us consider that the horizontal and vertical axes represent the class-limits and the frequencies of the class-intervals respectively.

The given data is a continuous grouped frequency distribution with equal class-intervals. To draw the frequency polygon of the given data without using histogram, obtain the class-limits of the class intervals. Obtain the class-limits of two class-intervals of 0 frequencies, i.e. on the horizontal axis, one adjacent to the first, on its left and one adjacent to the last, on its right. These class-intervals are known as imagined class-intervals. Then plot the frequencies against class-limits.

The following table is useful to draw the frequency polygon of the given data.

Class - Intervals Class - Marks Frequency 
55.5-62.5 59 0
62.5-69.5    
     
     
     
     
     
     
     
     
     
     

     
We represent class marks on X-axis on a suitable scale and the frequencies on Y-axis on a suitable scale.
To obtain the frequency polygon we plot the points (66, 1), (73, 3), (80, 5), (87, 15), (94, 12), (101, 10), (108, 6), (115, 4), (122, 3), (129, 1).
Now we join the plotted points by line segments. The end points (66, 1) and (129, 1) are joined to the mid points (59, 0) and ( 136, 0) respectively of imagined class intervals to obtain the frequency polygon.

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उत्तर २

We first draw horizontal and vertical axes. Let us consider that the horizontal and vertical axes represent the class-limits and the frequencies of the class-intervals respectively.

The given data is a continuous grouped frequency distribution with equal class-intervals. To draw the frequency polygon of the given data without using histogram, obtain the class-limits of the class intervals. Obtain the class-limits of two class-intervals of 0 frequencies, i.e. on the horizontal axis, one adjacent to the first, on its left and one adjacent to the last, on its right. These class-intervals are known as imagined class-intervals. Then plot the frequencies against class-limits.

The following table is useful to draw the frequency polygon of the given data.

Class - Intervals Class - Marks Frequency 
55.5-62.5 59 0
62.5-69.5 66 1
69.5 - 76.5 73 3
76.5 - 83.5 80 5
83.5 - 90.5 87 15
90.5 - 97.5 94 12
97.5-104.5 101 10
104-111.5 108 6
111.5 - 118.5 115 4
118.5-125.5 122 3
125.5-132.5 129 1
132.5-139.5 136 0

     
We represent class marks on X-axis on a suitable scale and the frequencies on Y-axis on a suitable scale.
To obtain the frequency polygon we plot the points (66, 1), (73, 3), (80, 5), (87, 15), (94, 12), (101, 10), (108, 6), (115, 4), (122, 3), (129, 1).
Now we join the plotted points by line segments. The end points (66, 1) and (129, 1) are joined to the mid points (59, 0) and ( 136, 0) respectively of imagined class intervals to obtain the frequency polygon.

 

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पाठ 23: Graphical Representation of Statistical Data - Exercise 23.3 [पृष्ठ ४२]

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आर.डी. शर्मा Mathematics [English] Class 9
पाठ 23 Graphical Representation of Statistical Data
Exercise 23.3 | Q 6 | पृष्ठ ४२

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

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The following table gives the distribution of students of two sections according to the mark obtained by them:-

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0 - 10 3 0 - 10 5
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20 - 30 17 20 - 30 15
30 - 40 12 30 - 40 10
40 - 50 9 40 - 50 1

Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections.


Read the bar graph shown in Fig. 23.8 and answer the following questions:

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(iv) State whether true or false.
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