मराठी

The distribution of heights (in cm) of 96 children is given below. Construct a histogram and a frequency polygon on the same axes.

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प्रश्न

The distribution of heights (in cm) of 96 children is given below. Construct a histogram and a frequency polygon on the same axes.

Height (in cm): 124
to
128
128
to
132
132
to
136
136
to
140
140
to
144
144
to
148
148
to
152
152
to
156
156
to
160
160
to
164
No. of Children: 5 8 17 24 16 12 6 4 3 1
थोडक्यात उत्तर
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उत्तर

To represent the given data by a histogram, we first draw horizontal and vertical axes. Let us consider that the horizontal and vertical axes represent the class-limits and the frequencies of the class-intervals respectively.

The given data is a continuous grouped frequency distribution with equal class-intervals. Construct rectangles with class-intervals as bases and respective frequencies as heights.
To draw the frequency polygon of the given data using histogram, obtain the mid-points of the upper horizontal side of each rectangle and then join these mid-points of the adjacent rectangles of the histogram by line segments. Obtain the mid-points of two class-intervals of 0 frequencies, i.e. on the horizontal axis, one adjacent to the first, on its left and one adjacent to the last, on its right. These class-intervals are known as imagined class-intervals. Complete the polygon by joining the mid-points of first and last class-intervals to the mid-points of imagined class-intervals adjacent to them. Let us take one vertical division is equal to 4.

The heights of the different rectangles are as following

1. The height of the rectangle corresponding to the class-interval 124-128 is `5/4 = 1.25` big divisions.

2. The height of the rectangle corresponding to the class-interval 128-132 is ` 8/4`=2` big divisions.

3. The height of the rectangle corresponding to the class-interval 132-136 is `17/4 = 4.25` big divisions.

4. The height of the rectangle corresponding to the class-interval 136-140 is  `24/4 = 6`  big divisions.

5. The height of the rectangle corresponding to the class-interval 140-144 is `16/4 = 4` big divisions.

6. The height of the rectangle corresponding to the class-interval 144-148 is  `12/4 = 3` big divisions.

7. The height of the rectangle corresponding to the class-interval 148-152 is  `6/4 = 1.5`  big divisions.

8. The height of the rectangle corresponding to the class-interval 152-156 is `4/4 =1 ` big divisions.

9. The height of the rectangle corresponding to the class-interval 156-160 is `3/4 = 0.75` big divisions.

10. The height of the rectangle corresponding to the class-interval 160-164 is `1/4 = 0.25 ` big divisions.

The histogram and frequency polygon of the given data is the following:

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पाठ 23: Graphical Representation of Statistical Data - Exercise 23.3 [पृष्ठ ४१]

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आर.डी. शर्मा Mathematics [English] Class 9
पाठ 23 Graphical Representation of Statistical Data
Exercise 23.3 | Q 2 | पृष्ठ ४१

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संबंधित प्रश्‍न

The length of 40 leaves of a plant are measured correct to one millimetre, and the obtained data is represented in the following table:-

Length (in mm) Number of leaves
118 - 126 3
127 - 135 5
136 - 144 9
145 - 153 12
154 - 162 5
163 - 171 4
172 - 180
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  2. Is there any other suitable graphical representation for the same data?
  3. Is it correct to conclude that the maximum number of leaves are 153 mm long? Why?

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In a histogram the class intervals or the group are taken along


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In a histogram, each class rectangle is constructed with base as


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(a) using histogram

(b) without using histogram

C.I

10 - 30

30 - 50

50 - 70 70 - 90 90 - 110 110 - 130 130 - 150
ƒ  4 7 5 9 5 6 4

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Tea-set

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Mixie

700 800

Coffee-maker

600 700

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600 500

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