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प्रश्न
The collector plate in an experiment on photoelectric effect is kept vertically above the emitter plate. A light source is put on and a saturation photocurrent is recorded. An electric field is switched on that has a vertically downward direction.
पर्याय
The photocurrent will increase.
The kinetic energy of the electrons will increase.
The stopping potential will decrease.
The threshold wavelength will increase.
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उत्तर
The kinetic energy of the electrons will increase.
As there is no effect of electric field on the number of photons emitted, the photoelectric current will remain same. Hence, option (a) is incorrect.
When an electric field is applied, then electric force will act on the electron moving opposite the direction of electric field, which will increase the kinetic energy of the electron. Hence, option (b) is correct.
As the kinetic energy of the electron is increasing, its stopping potential will increase. Hence, option (c) is incorrect.
Threshold wavelength is the characteristic property of the metal and will not change. Hence, (d) is incorrect.
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संबंधित प्रश्न
A mercury lamp is a convenient source for studying frequency dependence of photoelectric emission, since it gives a number of spectral lines ranging from the UV to the red end of the visible spectrum. In our experiment with rubidium photo-cell, the following lines from a mercury source were used:
λ1 = 3650 Å, λ2 = 4047 Å, λ3 = 4358 Å, λ4 = 5461 Å, λ5 = 6907 Å,
The stopping voltages, respectively, were measured to be:
V01 = 1.28 V, V02 = 0.95 V, V03 = 0.74 V, V04 = 0.16 V, V05 = 0 V
Determine the value of Planck’s constant h, the threshold frequency and work function for the material.
[Note: You will notice that to get h from the data, you will need to know e (which you can take to be 1.6 × 10−19 C). Experiments of this kind on Na, Li, K, etc. were performed by Millikan, who, using his own value of e (from the oil-drop experiment) confirmed Einstein’s photoelectric equation and at the same time gave an independent estimate of the value of h.]
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The graph shows the variation of photocurrent for a photosensitive metal
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The figure shows a plot of stopping potential (V0) versus `1/lambda`, where λ is the wavelength of the radiation causing photoelectric emission from a surface. The slope of the line is equal to ______.
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What is studied when light falls on a metal surface?
Which part is the photosensitive metal plate?
What changes the polarity between the plates?
Which plate is kept illuminated by monochromatic radiation?
Between which two parts is a potential difference applied?
What is used to change light frequency and study its effect on emission and electron energy?
Why does greater light intensity produce more emitted electrons?
What happens if the frequency of incident radiation is below the threshold frequency?
How quickly does photoelectric emission occur when suitable radiation falls on the metal surface?
