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Define the Terms "Stopping Potential' and 'Threshold Frequency' in Relation to Photoelectric Effect. How Does One Determine These Physical Quantities Using Einstein'S Equation?

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प्रश्न

Define the terms "stopping potential' and 'threshold frequency' in relation to the photoelectric effect. How does one determine these physical quantities using Einstein's equation?

थोडक्यात उत्तर
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उत्तर

Stopping potential:
For a particular frequency of incident radiation, the minimum negative (retarding) potential V0 given to the anode plate for which the photocurrent stops or becomes zero is called the cut-off or stopping potential.

Threshold frequency: 
There exists a certain minimum cut-off frequency ν0, for which the stopping potential is zero and below ν0 the electron emission is not possible.

This cut-off frequency is known as threshold frequency ν0, which is different for different metal. In the photoelectric effect, an electron absorbs a quantum of energy (hν ) of radiation. If this quantum of energy absorbed by electron exceeds the minimum energy required to come out of the metal surface by electron, the kinetic energy of the emitted electron is

`"K" = "hv" - phi`  ...(1)

Where `phi` is the minimum energy for electron to come out of the metal, and is different for different electrons in the metal. The maximum kinetic energy of photoelectrons is given by 

`"K""max" = "hv" - phi0`   ...(2)

Where, `phi0 - ` work function or least value of φ equation (2) is known as Einstein's photoelectric equation. 

Explanation of photoelectric effect with the help of Einstein's photoelectric equation

(i) According to equation (2), Kmax depends linearly on ν, and is independent of the intensity of radiation. This happens because, here, the photoelectric effect arises from the absorption of a single quantum of radiation by a single electron. The intensity of the radiation (that is proportional to the number of energy quanta per unit area per unit time) is irrelevant to this basic process.

(ii) Since Kmax must be non-negative, equation (2) implies that photoelectric emission is possible only if h ν > `phi0`.

or v > v0, where v0 = `"V"_0 = phi_0/"h"`

Thus, there exists a threshold frequency v0 `"V"_0 = phi_0/"h"` exists, below which photoelectric emission is not possible, and is independent of intensity.

(iii) As the intensity of radiation is proportional to the number of energy quanta per unit area per unit time. The greater the number of energy quanta available, the greater is the number of electrons absorbing the energy quanta, and therefore, the number of electrons coming out of the metal (for ν > ν0) is more and so is photoelectric current.

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2014-2015 (March) Ajmer Set 2

संबंधित प्रश्‍न

The following graph shows the variation of photocurrent for a photosensitive metal : 


(a) Identify the variable X on the horizontal axis.

(b) What does the point A on the horizontal axis represent?

(c) Draw this graph for three different values of frequencies of incident radiation v1, v2 and v3 (v1 > v2 > v3) for same intensity.

(d) Draw this graph for three different values of intensities of incident radiation I1, I2 and I3 (I1 > I2 > I3) having same frequency.


In an experiment on photoelectric effect, a photon is incident on an electron from one direction and the photoelectron is emitted almost in the opposite direction. Does this violate the principle of conservation of momentum?


The threshold wavelength of a metal is λ0. Light of wavelength slightly less than λ0 is incident on an insulated plate made of this metal. It is found that photoelectrons are emitted for some time and after that the emission stops. Explain.


If an electron has a wavelength, does it also have a colour?


Planck's constant has the same dimensions as


Calculate the momentum of a photon of light of wavelength 500 nm.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


The work function of a metal is 2.5 × 10−19 J. (a) Find the threshold frequency for photoelectric emission. (b) If the metal is exposed to a light beam of frequency 6.0 × 1014 Hz, what will be the stopping potential?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


The electric field associated with a light wave is given by  `E = E_0 sin [(1.57 xx 10^7  "m"^-1)(x - ct)]`. Find the stopping potential when this light is used in an experiment on photoelectric effect with the emitter having work function 1.9 eV.


Consider a 20 W bulb emitting light of wavelength 5000 Å and shining on a metal surface kept at a distance 2 m. Assume that the metal surface has work function of 2 eV and that each atom on the metal surface can be treated as a circular disk of radius 1.5 Å.

  1. Estimate no. of photons emitted by the bulb per second. [Assume no other losses]
  2. Will there be photoelectric emission?
  3. How much time would be required by the atomic disk to receive energy equal to work function (2 eV)?
  4. How many photons would atomic disk receive within time duration calculated in (iii) above?
  5. Can you explain how photoelectric effect was observed instantaneously?

What is the effect of threshold frequency and stopping potential on increasing the frequency of the incident beam of light? Justify your answer.


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