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What is the Speed of a Photon with Respect to Another Photon If (A) the Two Photons Are Going in the Same Direction and (B) They Are Going in Opposite Directions? - Physics

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प्रश्न

What is the speed of a photon with respect to another photon if (a) the two photons are going in the same direction and (b) they are going in opposite directions?

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उत्तर

(a) In relativity, the relative speed of two objects `(v_(rel))` moving in the same direction with speeds u and v is given by `v_(rel) = (u - v)/(1-(uv)/c^2)` ...(1)

As the photons are moving with the speed of light, u = c and v = c.
 On substituting the values of u and v in equation (1), we get :

`v_(rel) = 0`

Thus, relative velocity of a photon with respect to another photon will be 0, when they are going in the same direction.
(b) In relativity, relative speed of two objects moving in opposite directions with speeds u and v is given by

`v_(rel) = (u+v)/(1+(uv)/c^2)`     ....(2)

We know that a photon travels with the speed of light. Therefore, u = c and v = c
   On substituting the values of u and v in equation (2), we get : 

`v_(rel) = c` 

Thus, the relative velocity of a photon with respect to another photon will be equal to the speed of light when they are going in opposite directions.

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Experimental Study of Photoelectric Effect
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 20: Photoelectric Effect and Wave-Particle Duality - Short Answers [पृष्ठ ३६३]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 20 Photoelectric Effect and Wave-Particle Duality
Short Answers | Q 3 | पृष्ठ ३६३

संबंधित प्रश्‍न

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(b) the maximum kinetic energy of photoelectrons depends only on the frequency of light and not on its intensity
(c) even when the metal surface is faintly illuminated the photoelectrons leave the surface immediately
(d) electric charge of the photoelectrons is quantised


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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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Wavelength (nm):         350   400   450   500   550
Stopping potential (V): 1.45  1.00  0.66  0.38  0.16

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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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What is the effect of threshold frequency and stopping potential on increasing the frequency of the incident beam of light? Justify your answer.


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