मराठी

Show that y = log(1+x)-2x2+x,x>- 1, is an increasing function of x throughout its domain. - Mathematics

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प्रश्न

Show that y = `log(1+x) - (2x)/(2+x), x> -  1`, is an increasing function of x throughout its domain.

बेरीज
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उत्तर

We have,

y = log `(1 + x) - (2x) / (2 + x), x > -1`

Here, `dy/dx = 1/ (1 + x) - 2  d/dx  (x/ (2 +x))`

`1/ (1 + x) - 2  {(2 + x) * 1- x (0 +1)}/(2 + x)^2`

`1/ (1 +x) - 4/ (2 + x)^2 = ((2 + x)^2 - 4 (1 + x))/((1 + x) (2 + x)^2)`

`= x^2/((1 + x) (2 + x)^2) AA x > - 1` 

x2 > 0, (2 + x)2 >0 (being perfect square) and  (1 + x) > 0 ∀ x> -1

`dy/dx>= 0` for all x > -1

Hence, y is an increasing function of x throughout its domain.

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पाठ 6: Application of Derivatives - Exercise 6.2 [पृष्ठ २०५]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 6 Application of Derivatives
Exercise 6.2 | Q 7 | पृष्ठ २०५

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