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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Solve the following : Find the intervals on which the function f(x) = xlogx is increasing and decreasing.

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प्रश्न

Solve the following:

Find the intervals on which the function f(x) = `x/logx` is increasing and decreasing.

बेरीज
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उत्तर

f(x) = `x/logx`

∴ f'(x) = `d/dx(x/logx)`

= `((logx).d/dx(x) - x*d/dx(logx))/(logx)^2`

= `((logx) xx 1 - x xx 1/x)/(logx)^2`

= `(logx - 1)/(log x)^2`

f is increasing if f'(x) ≥ 0

i.e. if `(log x - 1)/(logx)^2 ≥ 0`

i.e. if log x – 1 ≥ 0          ...[∵ (log x)2 > 0]

i.e. if log x ≥ 1

i.e. if log x ≥ log e          ...[∵  log e = 1]

i.e. if x ≥ e

∴ f is increasing on `[e, oo)`

f is decreasing if f'(x) ≤ 0

i.e. if `(log x - 1)/(logx)^2 ≤ 0`

i.e. if log x – 1 ≤ 0                        ...[∵ (log x)2 > 0]

i.e. if log x ≤ 1

i.e. if log x ≤ log e

i.e. if x ≤ e

Also, x > 0 and x ≠ 1 because f(x) = `x/logx` is not defined at x = 1

∴ f is decreasing in (0, e] – {1}

Hence, f is increasing in `[e, oo)` and decreasing in (0, e] – {1}.

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पाठ 2: Applications of Derivatives - Miscellaneous Exercise 2 [पृष्ठ ९३]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 2 Applications of Derivatives
Miscellaneous Exercise 2 | Q 11 | पृष्ठ ९३

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