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Show that the function given by f(x) = 3x + 17 is strictly increasing on R. - Mathematics

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प्रश्न

Show that the function given by f(x) = 3x + 17 is strictly increasing on R.

बेरीज
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उत्तर

We have f(x) = 3x + 17

f(x) being a polynomial function, is continuous and derivable on R.

f'(x) `3 > 0, x in R`

⇒ f is strictly increasing on R.

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पाठ 6: Application of Derivatives - Exercise 6.2 [पृष्ठ २०५]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 6 Application of Derivatives
Exercise 6.2 | Q 2 | पृष्ठ २०५

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