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Prove that F(X) = Ax + B, Where A, B Are Constants and a < 0 is a Decreasing Function on R ? - Mathematics

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प्रश्न

Prove that f(x) = ax + b, where a, b are constants and a < 0 is a decreasing function on R ?

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उत्तर

\[f\left( x \right) = ax + b\]

\[\text { Let }x_1 , x_2 \text { in R such that } x_1 < x_2 . \]

\[\text { Then },\]

\[ x_1 < x_2 \]

\[ \Rightarrow a x_1 > a x_2 (\because a<0)\]

\[ \Rightarrow a x_1 + b > a x_2 + b\]

\[ \Rightarrow f\left( x_1 \right) > f\left( x_2 \right)\]

\[\text { Thus }, x_1 < x_2 \]

\[ \Rightarrow f\left( x_1 \right) > f\left( x_2 \right), \forall x_1 , x_2 \in R\]

\[\text { So },f\left( x \right) \text { is decreasing on R } .\]

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पाठ 17: Increasing and Decreasing Functions - Exercise 17.1 [पृष्ठ १०]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 17 Increasing and Decreasing Functions
Exercise 17.1 | Q 4 | पृष्ठ १०

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