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Show That F(X) = Log Sin X Is Increasing on (0, π/2) and Decreasing on (π/2, π) ? - Mathematics

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प्रश्न

Show that f(x) = log sin x is increasing on (0, π/2) and decreasing on (π/2, π) ?

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उत्तर

\[\text { Here }, \]

\[f\left( x \right) = \log \sin x\]

\[\text { Domain of log sin x is}\left( 0, \pi \right).\]

\[f'\left( x \right) = \frac{1}{\sin x}\cos x\]

\[ = \cot x\]

\[\text { For x} \in \left( 0, \frac{\pi}{2} \right), \text { cot x} > 0 \left[ \because \text { Cot function is positive in first quadrant }\right]\]

\[ \Rightarrow f'\left( x \right) > 0 \]

\[\text { So,f(x)is increasing on} \left( 0, \frac{\pi}{2} \right) . \]

\[\text { For x }\in \left( \frac{\pi}{2}, \pi \right), \text { cot x }< 0 \left[ \because \text { Cot function is negative in second quadrant } \right]\]

\[ \Rightarrow f'\left( x \right) < 0 \]

\[\text { So,f(x)is decreasing on }\left( \frac{\pi}{2}, \pi \right).\]

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पाठ 17: Increasing and Decreasing Functions - Exercise 17.2 [पृष्ठ ३४]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 17 Increasing and Decreasing Functions
Exercise 17.2 | Q 8 | पृष्ठ ३४

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