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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the values of x for which the following functions are strictly decreasing : f(x) = 2x3 – 3x2 – 12x + 6

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प्रश्न

Find the values of x for which the following functions are strictly decreasing:

f(x) = 2x3 – 3x2 – 12x + 6

बेरीज
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उत्तर

f(x) = 2x3 – 3x2 – 12x + 6

∴ f'(x) = `d/dx(2x^3 - 3x^2 - 12x + 6)`

= 2 × 3x2 – 3 × 2x – 12 × 1 + 0

= 6x2 – 6x – 12

= 6(x2 – x – 2)

f is strictly decreasing if f'(x) < 0

i.e. if 6(x2 – x – 2) < 0

i.e. if x2 – x – 2 < 0

i.e. if x2 – x < 2

i.e. if `x^2 - x + (1)/(4) < 2 + (1)/(4)`

i.e. if `(x - 1/2)^2 < (9)/(4)`

i.e. if `-(3)/(2) < x - (1)/(2) < (3)/(2)`

i.e. if `-(3)/(2) + (1)/(2) < x -(1)/(2) + (1)/(2) < (3)/(2) + (1)/(2)`

i.e. if – 1 < x < 2

∴ f is strictly decreasing if – 1 < x < 2

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पाठ 2: Applications of Derivatives - Exercise 2.4 [पृष्ठ ८९]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 2 Applications of Derivatives
Exercise 2.4 | Q 3.1 | पृष्ठ ८९

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