मराठी

Show that the function f: R → R defined by f(x) = xx2+1, ∀ ∈ + R , is neither one-one nor onto

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प्रश्न

Show that the function f: R → R defined by f(x) = `x/(x^2 + 1)`, ∀ ∈ + R , is neither one-one nor onto

बेरीज
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उत्तर

For x1 , x2 ∈ R, consider

f(x1) = f(x2)

⇒ `x_1/(x_1^2 + 1) = x_2/(x_2^2 + 1)`

⇒ `x_1  x_2^2 + x_1 = x_2  x_1^2 + x_2`

⇒ x1 x2 (x2 – x1) = x2 – x1

⇒ x1 = x2 or x1 x2 = 1

We note that there are point, x1 and x2 with x1 ≠ x2 and if f(x1) = f(x2), for instance, If we take x1 = 2 and x2 = `1/2`, then we have f(x1) = `2/5` and f(x2) = `2/5` but `2 ≠ 1/2`.

Hence f is not one-one. Also, f is not onto for if so then for 1∈R ∃ x ∈ R such that f(x) = 1 which gives `x/(x^2 + 1)` = 1

But there is no such x in the domain R, since the equation x2 – x + 1 = 0 does not give any real value of x.

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पाठ 1: Relations And Functions - Solved Examples [पृष्ठ ५]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
पाठ 1 Relations And Functions
Solved Examples | Q 13 | पृष्ठ ५

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