मराठी

∫ Log X X N D X - Mathematics

Advertisements
Advertisements

प्रश्न

\[\int\frac{\log x}{x^n}\text{  dx }\]
बेरीज
Advertisements

उत्तर

`  ∫   1/x^n   log  x   dx `
`  " Taking  log x as the first function and "{1}/ {x^n}"  as the second function  " ` 
\[ = \log x\int\frac{1}{x^n}dx - \int\left( \frac{d}{dx}\log x\int\frac{1}{x^n}dx \right)dx\]
\[ = \log x\left( \frac{x^{- n + 1}}{- n + 1} \right) - \int\frac{1}{x}\left( \frac{x^{- n + 1}}{- n + 1} \right)dx\]
\[ = \log x\left( \frac{x^{- n + 1}}{- n + 1} \right) - \int\frac{x^{- n}}{- n + 1}dx\]
\[ = \log x\left( \frac{x^{- n + 1}}{- n + 1} \right) - \frac{x^{- n + 1}}{\left( - n + 1 \right)^2} + C\]
\[ = \log x\left( \frac{x^{1 - n}}{1 - n} \right) - \frac{x^{1 - n}}{\left( 1 - n \right)^2} + C\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 19: Indefinite Integrals - Exercise 19.25 [पृष्ठ १३३]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.25 | Q 15 | पृष्ठ १३३

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

\[\int\frac{\sin^3 x - \cos^3 x}{\sin^2 x \cos^2 x} dx\]

\[\int \cot^{- 1} \left( \frac{\sin 2x}{1 - \cos 2x} \right) dx\]

\[\int \left( a \tan x + b \cot x \right)^2 dx\]

\[\int\frac{1}{\text{cos}^2\text{ x }\left( 1 - \text{tan x} \right)^2} dx\]

\[\int x^2 e^{x^3} \cos \left( e^{x^3} \right) dx\]

\[\int\frac{e^\sqrt{x} \cos \left( e^\sqrt{x} \right)}{\sqrt{x}} dx\]

\[\int 5^{x + \tan^{- 1} x} . \left( \frac{x^2 + 2}{x^2 + 1} \right) dx\]

\[\int\frac{e^{m \tan^{- 1} x}}{1 + x^2} dx\]

\[\int\frac{x}{\sqrt{x^2 + a^2} + \sqrt{x^2 - a^2}} dx\]

` ∫   tan   x   sec^4  x   dx  `


\[\int {cosec}^4  \text{ 3x } \text{ dx } \]

\[\int\frac{1}{\sin^3 x \cos^5 x} dx\]

\[\int\frac{1}{\sqrt{\left( 2 - x \right)^2 - 1}} dx\]

\[\int\frac{x}{x^4 + 2 x^2 + 3} dx\]

\[\int\frac{3 x^5}{1 + x^{12}} dx\]

\[\int\frac{x - 1}{3 x^2 - 4x + 3} dx\]

\[\int\frac{5x + 3}{\sqrt{x^2 + 4x + 10}} \text{ dx }\]

\[\int\frac{1}{1 + 3 \sin^2 x} \text{ dx }\]

\[\int\frac{1}{1 - \sin x + \cos x} \text{ dx }\]

\[\int\frac{1}{1 - \cot x} dx\]

\[\int \tan^{- 1} \left( \frac{2x}{1 - x^2} \right) \text{ dx }\]

\[\int\sqrt{3 - x^2} \text{ dx}\]

\[\int\frac{x^3 - 1}{x^3 + x} dx\]

\[\int\frac{2x + 1}{\left( x - 2 \right) \left( x - 3 \right)} dx\]

\[\int\frac{1}{x^4 - 1} dx\]

\[\int\frac{\left( x^2 + 1 \right) \left( x^2 + 2 \right)}{\left( x^2 + 3 \right) \left( x^2 + 4 \right)} dx\]

 


\[\int\frac{x^2}{\left( x - 1 \right) \sqrt{x + 2}}\text{  dx}\]

\[\int\frac{x}{\left( x^2 + 2x + 2 \right) \sqrt{x + 1}} \text{ dx}\]

Write a value of

\[\int e^{3 \text{ log x}} x^4\text{ dx}\]

If \[\int\frac{1}{5 + 4 \sin x} dx = A \tan^{- 1} \left( B \tan\frac{x}{2} + \frac{4}{3} \right) + C,\] then


\[\int\frac{\sin x}{\sqrt{1 + \sin x}} dx\]

\[\int\frac{1}{1 - x - 4 x^2}\text{  dx }\]

\[\int\frac{\sin^2 x}{\cos^6 x} \text{ dx }\]

\[\int \sec^6 x\ dx\]

\[\int \tan^5 x\ \sec^3 x\ dx\]

\[\int\sqrt{x^2 - a^2} \text{ dx}\]

\[\int\sqrt{3 x^2 + 4x + 1}\text{  dx }\]

\[\int\frac{\log x}{x^3} \text{ dx }\]

\[\int\frac{\cot x + \cot^3 x}{1 + \cot^3 x} \text{ dx}\]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×