मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

If there were only one type of charge in the universe, then ______. ∮s E.dS ≠ 0 on any surface. ∮s E.dS = 0 if the charge is outside the surface. ∮s E.dS could not be defined. ∮s E.dS = εqε0

Advertisements
Advertisements

प्रश्न

If there were only one type of charge in the universe, then ______.

  1. `oint_s` E.dS ≠ 0 on any surface.
  2. `oint_s` E.dS = 0 if the charge is outside the surface.
  3. `oint_s` E.dS could not be defined.
  4. `oint_s` E.dS = `q/ε_0` if charges of magnitude q were inside the surface.

पर्याय

  • a and d

  • a and c

  • b and d

  • c and d

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

b and d

Explanation:

From Gauss’ law, we know `oint_s` E.dS = `q/ε_0`, here q is the charge enclosed by the closed surface. If `oint_s` E.dS =  0 then q = 0, i.e., net charge enclosed by the surface must be zero. If the charge is outside the surface, then charge enclosed by the surface is q = 0 and thus, `oint` E.dS = 0.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Electric Charges And Fields - MCQ I [पृष्ठ ४]

APPEARS IN

एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 12
पाठ 1 Electric Charges And Fields
MCQ I | Q 1.1 | पृष्ठ ४

संबंधित प्रश्‍न

State and explain Gauss’s law.


A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in the Figure. What is the magnitude of the electric flux through the square? (Hint: Think of the square as one face of a cube with edge 10 cm.)


A charge ‘q’ is placed at the centre of a cube of side l. What is the electric flux passing through each face of the cube?


A thin conducting spherical shell of radius R has charge Q spread uniformly over its surface. Using Gauss’s law, derive an expression for an electric field at a point outside the shell.


State Gauss’s law for magnetism. Explain its significance. 


Answer the following question.
State Gauss's law for magnetism. Explain its significance.


Gaussian surface cannot pass through discrete charge because ____________.


Gauss's law is valid for ______.

Which of the following statements is not true about Gauss’s law?


Five charges q1, q2, q3, q4, and q5 are fixed at their positions as shown in figure. S is a Gaussian surface. The Gauss’s law is given by `oint_s E.ds = q/ε_0`

Which of the following statements is correct?


If `oint_s` E.dS = 0 over a surface, then ______.

  1. the electric field inside the surface and on it is zero.
  2. the electric field inside the surface is necessarily uniform.
  3. the number of flux lines entering the surface must be equal to the number of flux lines leaving it.
  4. all charges must necessarily be outside the surface.

Consider a region inside which there are various types of charges but the total charge is zero. At points outside the region

  1. the electric field is necessarily zero.
  2. the electric field is due to the dipole moment of the charge distribution only.
  3. the dominant electric field is `∞ 1/r^3`, for large r, where r is the distance from a origin in this region.
  4. the work done to move a charged particle along a closed path, away from the region, will be zero.

An arbitrary surface encloses a dipole. What is the electric flux through this surface?


If the total charge enclosed by a surface is zero, does it imply that the elecric field everywhere on the surface is zero? Conversely, if the electric field everywhere on a surface is zero, does it imply that net charge inside is zero.


The region between two concentric spheres of radii a < b contain volume charge density ρ(r) = `"c"/"r"`, where c is constant and r is radial- distanct from centre no figure needed. A point charge q is placed at the origin, r = 0. Value of c is in such a way for which the electric field in the region between the spheres is constant (i.e. independent of r). Find the value of c:


In finding the electric field using Gauss law the formula `|vec"E"| = "q"_"enc"/(epsilon_0|"A"|)` is applicable. In the formula ε0 is permittivity of free space, A is the area of Gaussian surface and qenc is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?


A charge Q is placed at the centre of a cube. The electric flux through one of its faces is ______.


A charge of +5 μC is placed at the centre of two concentric spheres of radii r1 = 3 cm and r2 = 5 cm. The ratio of the flux through sphere of radius r1 to that through sphere of radius r2 will be ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×