मराठी

A charge Q is placed at the centre of a cube. The electric flux through one of its faces is ______.

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प्रश्न

A charge Q is placed at the centre of a cube. The electric flux through one of its faces is ______.

पर्याय

  • `Q/epsi_0`

  • `Q/(6epsi_0)`

  • `Q/(8epsi_0)`

  • `Q/(3epsi_0)`

MCQ
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उत्तर

A charge Q is placed at the centre of a cube. The electric flux through one of its faces is `underlinebb(Q/(6epsi_0))`.

Explanation:

Assuming the cube as a Gaussian surface, the total flux passing through the cube of side l can be given as,

`phi = Q/epsi_0`

Flux through each face of the cube: As the charge is placed symmetrically to each face of the cube, thus electric flux passing through each face is equal.

∴ Electric flux passing through each face,

`phi^' = phi/6 = Q/(6epsi_0)`

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2022-2023 (March) Delhi Set 2

संबंधित प्रश्‍न

State and explain Gauss’s law.


A thin conducting spherical shell of radius R has charge Q spread uniformly over its surface. Using Gauss’s law, derive an expression for an electric field at a point outside the shell.


A charge Q is placed at the centre of a cube. Find the flux of the electric field through the six surfaces of the cube.


Answer the following question.
State Gauss's law for magnetism. Explain its significance.


Gauss’s law is true only if force due to a charge varies as ______.

Gauss's law is valid for ______.

The Electric flux through the surface


(i)

(ii)

(iii)

(iv)

Consider a region inside which there are various types of charges but the total charge is zero. At points outside the region

  1. the electric field is necessarily zero.
  2. the electric field is due to the dipole moment of the charge distribution only.
  3. the dominant electric field is `∞ 1/r^3`, for large r, where r is the distance from a origin in this region.
  4. the work done to move a charged particle along a closed path, away from the region, will be zero.

If the total charge enclosed by a surface is zero, does it imply that the elecric field everywhere on the surface is zero? Conversely, if the electric field everywhere on a surface is zero, does it imply that net charge inside is zero.


In finding the electric field using Gauss law the formula `|vec"E"| = "q"_"enc"/(epsilon_0|"A"|)` is applicable. In the formula ε0 is permittivity of free space, A is the area of Gaussian surface and qenc is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?


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