मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Give plausible explanation for the following: There are two −NH2 groups in semicarbazide. However, only one is involved in the formation of semicarbazones.

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प्रश्न

Give plausible explanation for the following:

There are two −NH2 groups in semicarbazide. However, only one is involved in the formation of semicarbazones.

रासायनिक समीकरणे/रचना
कारण सांगा
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उत्तर

Semicarbazide only has one of the two −NH2 groups resonance and this group is directly attached to the carbonyl-carbon atom.

Therefore, the electron density on −NH2 group involved in the resonance also decreases. As a result, it cannot act as a nucleophile. Since the other −NH2 group is not involved in resonance, it can act as a nucleophile and attack carbonyl-carbon atoms of aldehydes and ketones to produce semicarbazones.

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पाठ 8: Aldehydes, Ketones and Carboxylic Acids - Exercises [पृष्ठ २५७]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 8 Aldehydes, Ketones and Carboxylic Acids
Exercises | Q 8.18 (ii) | पृष्ठ २५७

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The carbon-oxygen double bond is polarised in aldehydes and ketones due to higher electronegativity of oxygen relative to carbon. Therefore, they undergo nucleophilic addition reactions with a number of nucleophiles such as HCN, NaHSO3, alcohols, ammonia derivatives and Grignard reagents. Aldehydes are easily oxidised by mild oxidising agents as compared to ketones. The carbonyl group of carboxylic acid does not give reactions of aldehydes and ketones. Carboxylic acids are considerably more acidic than alcohols and most of simple phenols.

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CH3CHO, \[\begin{array}{cc}
\ce{(CH3)3C-C-CH3}\\
\phantom{....}||\\
\phantom{....}\ce{O}
\end{array}\],  \[\begin{array}{cc}
\ce{CH3-C-CH3}\\
||\\
\ce{O}
\end{array}\]

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OR

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(i)
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[C] is __________.


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