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Different points in earth are at slightly different distances from the sun and hence experience different forces due to gravitation. - Physics

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प्रश्न

Different points in earth are at slightly different distances from the sun and hence experience different forces due to gravitation. For a rigid body, we know that if various forces act at various points in it, the resultant motion is as if a net force acts on the c.m. (centre of mass) causing translation and a net torque at the c.m. causing rotation around an axis through the c.m. For the earth-sun system (approximating the earth as a uniform density sphere).

पर्याय

  • the torque is zero.

  • the torque causes the earth to spin.

  • the rigid body result is not applicable since the earth is not even approximately a rigid body.

  • the torque causes the earth to move around the sun.

MCQ
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उत्तर

The torque is zero.

Explanation:

As the earth is revolving around the sun in a circular motion due to gravitational attraction. The force of attraction will be of radial nature i.e., the angle between position vector r and force F is zero. So, torque = |τ| = |r × F| = rFsin0° = 0.

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पाठ 8: Gravitation - Exercises [पृष्ठ ५८]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
पाठ 8 Gravitation
Exercises | Q 8.3 | पृष्ठ ५८

संबंधित प्रश्‍न

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What happens to the force between two objects, if the masses of both objects are doubled?


Write the three laws given by Kepler. How did they help Newton to arrive at the inverse square law of gravity?


The weight of an object is more at the poles than at the equator. Is it beneficial to purchase goods at equator and sell them at the pole? Does it matter whether a spring balance is used or an equal-beam balance is used?


Three equal masses m are placed at the three corners of an equilateral triangle of side a. Find the force exerted by this system on another particle of mass m placed at (a) the mid-point of a side, (b) at the centre of the triangle.


A semicircular wire has a length L and mass M. A particle of mass m is placed at the centre of the circle. Find the gravitational attraction on the particle due to the wire.


A solid sphere of mass m and radius r is placed inside a hollow thin spherical shell of mass M and radius R as shown in the following figure . A particle of mass m' is placed on the line joining the two centres at a distance x from the point of contact of the sphere and the shell. Find the magnitude of the resultant gravitational force on this particle due to the sphere and the shell if (a) r < x < 2r, (b) 2r < x < 2R and (c) x > 2R.


Write an expression for the gravitational force of attraction between two bodies of masses m1 and m2 separated by a distance r.


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Where will you weigh more: at the centre of the earth or at the surface of the earth?


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Explain the difference between g and G.


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Answer the following question.

What are the dimensions of the universal gravitational constant?


What do you mean by a gravitational constant?


If the law of gravitation, instead of being inverse-square law, becomes an inverse-cube law- ______.

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  3. projectile motion of a stone thrown by hand on the surface of the earth will be approximately parabolic.
  4. there will be no gravitational force inside a spherical shell of uniform density.

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