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Derive an expression for capillary rise for a liquid having a concave meniscus. - Physics

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प्रश्न

Derive an expression for capillary rise for a liquid having a concave meniscus.

व्युत्पत्ती
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उत्तर

The pressure due to the liquid (water) column of height h must be equal to the pressure difference 2T/R due to the concavity.

`therefore hrhog=(2T)/R`

where, ρ is the density of the liquid and g is acceleration due to gravity.

Let r be the radius of the capillary tube and θ be the angle of contact of the liquid as shown in the figure.

Then radius of curvature R of the meniscus is given by,

`R=r/costheta`

`therefore hrhog=(2Tcostheta)/r`

`therefore h=(2Tcostheta)/(rrhog)`

The above equation gives the expression for capillary rise (or fall) for a liquid. Narrower the tube, the greater is the height to which the liquid rises (or falls).

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पाठ 2: Mechanical Properties of Fluids - Exercises [पृष्ठ ५४]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
पाठ 2 Mechanical Properties of Fluids
Exercises | Q 9 | पृष्ठ ५४

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