मराठी

Consider F : {1, 2, 3} → {A, B, C} And G : {A, B, C} → {Apple, Ball, Cat} Defined As F (1) = A, F (2) = B, F (3) = C, G (A) = Apple, G (B) = Ball And G (C) = Cat. Show That F, G And Gof

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प्रश्न

Consider f : {1, 2, 3} → {abc} and g : {abc} → {apple, ball, cat} defined as f (1) = af (2) = bf (3) = cg (a) = apple, g (b) = ball and g (c) =  cat. Show that fg and gof are invertible. Find f−1g−1 and gof−1and show that (gof)−1 = f 1o g−1

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उत्तर

 f = { ( 1, a ) . (2, b) , (c , 3 ) } and g = {(a , apple) , (b , ball) , (c , cat)} Clearly , f and g are bijections.

So, f and g are invertible. 

Now,

 f -1 = {(a ,1) , (b , 2) , (3,c)} and g-1 = {(apple, a ) , (ball ,b), (cat , c)}

So, f-1 o g-1= {apple , 1} , (ball,2), (cat , 3 )} ......... (1)

f : {1,2,3,} → {a,b,c} and g : {a,b,c} → {apple , ball , cat}

So, gof : {1.2.3} → {apple , ball, cat}

⇒ (gof) (1) =g (f(1)) = g (a) = apple

(gof) (2) = g (f (2)) = g (b) = ball,

and (gof) (3) = g (f(3)) = g (c) cat 

∴ gof = {(1 . apple) ,(2, ball) , (3 , cat)}

Clearly , gof is a bijection.

So, gof is invertible. 

(gof)-1 = {(apple , 1), (ball,2),(cat , 3)}  ....... (2)

Form (1) and (2) , we get :

(gof)-1 = f-1 o g -1

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पाठ 2: Functions - Exercise 2.4 [पृष्ठ ६८]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 2 Functions
Exercise 2.4 | Q 3 | पृष्ठ ६८

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