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प्रश्न
Complete the following diagrams shown in the below figure by drawing the reflected ray for each incident ray.

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उत्तर

A light ray when produced backwards passes through principal focus as shown in the problem figure. We draw the normal through the centre of curvature at the point of incidence and draw the reflected ray at an angle equal to the angle of incidence thus following the laws of reflection. The reflected ray is parallel to the principal axis. The other ray is passing through the centre of curvature as shown in the problem figure. This ray retraces its incident path because it strikes the mirror normally i.e. 90 degrees. These two reflected rays when produced backwards coincide at a point where the image is formed. The image, A'B' is virtual, erect, and diminished in size.
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संबंधित प्रश्न
What happens when a ray of light falls normally (or perpendiculary) on the surface of a plane mirror?
Name the spherical mirror which has:
(a) virtual principal focus.
(b) real principal focus.
The shiny outer surface of a hollow sphere of aluminium of radius 50 cm is to be used as a mirror:
- What will be the focal length of this mirror?
- Which type of spherical mirror will it provide?
- State whether this spherical mirror will diverge or converge light rays.
Name the kind of mirror used to obtain :
A real and enlarged image
The image formed by a convex mirror is of size one third the size of object. How are u and v related?
Define the following term in relation to concave mirror.
Principal focus
The boxes in figure (a, b, c) represent mirrors; insert a mirror which will reflect the incident ray as shown in the diagram.

Which of the following has curved reflecting surface?
Numerical problem.
The radius of curvature of a spherical mirror is 25 cm. Find its focal length.
