Advertisements
Advertisements
प्रश्न
A train takes 2 h to reach station B from station A, and then 3 h to return from station B to station A. The distance between the two stations is 200 km. Find:
The average speed,
The average velocity of the train.
Advertisements
उत्तर
Here, total distance = (200 + 200) km = 400 km
Total time taken = (2 + 3) h = 5 h
(i) Average speed = Total distance travelled/total time taken = `(400 "km")/(5 "h")` = 80 km h-1
(ii) Average velocity of the train is zero because the train stops at the same point from where it starts, i.e. the displacement is zero.
APPEARS IN
संबंधित प्रश्न
What is the Differnece between speed and velocity ?
What is the SI unit of retardation ?
Arrange the following speed in increasing order (keeping the least speed first):
An athlete running with a speed of 10 m/s.
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
How long does it take to travel 240 m ?
A car is moving on a straight road with uniform acceleration. The speed of the car varies with time as follows :
Time (s) : 0 2 4 6 8 10
Speed (m/s) : 4 8 12 16 20 24
Draw the speed-time graph by choosing a convenient scale. From this graph :
(1) Calculate the acceleration of the car.
(2) Calculate the distance travelled by the car in 10 seconds.
The graph given alongside shows how the speed of a car changes with time:
(i) What is the initial speed of the car ?
(ii) What is the maximum speed attained by the car ?
(iii) Which part of the graph shows zero acceleration ?
(iv) Which part of the graph shows varying retardation ?
(v) Find the distance travelled in first 8 hours.
The speed of a moving object is determined to be 0.06 m/s. This speed is equal to :
When is a body said to be in motion?
Arrange the following speeds in increasing order.
10 m s-1, 1 km min-1 and 18 km h-1.
The velocity-time graph of a moving body is given below in Figure
The acceleration in parts AB, BC and CD.
