Advertisements
Advertisements
प्रश्न
A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?
Advertisements
उत्तर
Given side of square field = 10m
Then the perimeter of that square field = 4 × 10
= 40m
Total time = 2 minute 20 sec
= (2 × 60 + 20)
= 140 sec
Hence, the distance covered in going around the square field = perimeter of the field
Total distance covered in 40 sec = 40m
Total distance covered in 140 sec = `(40/40) xx140` m
= 140 m
This number of rounds = `140/40`
= 3.5
In 140 sec, that farmer will take 3.5 rounds.
Displacement = Diagonal of square = `(102+102) 1/2`
= `(200)1/2`
= `10sqrt2` m
Hence, magnitude of displacement = `10sqrt2` m
APPEARS IN
संबंधित प्रश्न
Under what conditions can a body travel a certain distance and yet its resultant displacement be zero ?
When is the magnitude of displacement equal to the distance?
A body at rest is made to fall from the top of a tower. Its displacement at different instants is given in the following table:
| Time (in s) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 |
| Displacement (in m) | 0.05 | 0.20 | 0.45 | 0.80 | 1.25 | 1.80 |
Draw a displacement-time graph and state whether the motion is uniform or non-uniform?
A ball moves on a smooth floor in a straight line with uniform velocity 10 m s-1 for 6 s. At t = 6 s, the ball hits a wall and comes back along the same line to the starting point with the same speed. Draw the velocity-time graph and use it to find the total distance travelled by the ball and its displacement.
Figure shows the velocity-time graph of a particle moving in a straight line.
(i) State the nature of motion of particle.
(ii) Find the displacement of particle at t = 6 s.
(iii) Does the particle change its direction of motion?
(iv) Compare the distance travelled by the particle from 0 to 4 s and from 4 s to 6 s.
(v) Find the acceleration from 0 to 4 s and retardation from 4 s to 6 s.
Write an expression for the distance S covered in time t by a body which is initially at rest and starts moving with a constant acceleration a.
Draw displacement – time graph for the following situation:
When a body is moving with variable velocity.
Is distance covered during nth second more than the distance covered in n seconds?
Name the physical quantity associated with the rate of change of displacement with time.
A scalar quantity has ______.
