Advertisements
Advertisements
प्रश्न
A cyclist driving at 5 ms−1, picks a velocity of 10 ms−1, over a distance of 50 m. Calculate
- acceleration
- time in which the cyclist picks up above velocity.
Advertisements
उत्तर
Initial velocity = u = 5 ms−1
Final velocity = v = 10 ms−1
Distance = S =50 m
(i) v2 – u2 = 2aS
(10)2 – (5)2 = 2a (50)
100 − 25 = 100a
100a = 75
a = `75/100` = 0.75 ms−2
∴ Acceleration = a = 0.75 ms−2
(ii) v = u + at
10 = 5 + 0.75t
0.75t = 10 − 5 = 5
(Time) t = `5/0.75` = 6.67 S
APPEARS IN
संबंधित प्रश्न
A toy car initially moving with uniform velocity of 18 km h-1 comes to a stop in 2 s. Find the retardation of the car in S.I. units.
Figure shows the velocity-time graphs for two cars A and B moving in the same direction. Which car has greater acceleration? Give reasons to your answer.
A truck running at 90 kmh−1, is brought to rest over a distance of 25 m. Calculate the retardation and time for which brakes are applied.
A motor bike running at 5 ms−1, picks up a velocity of 30 ms−1 in 5s. Calculate
- acceleration
- distance covered during acceleration.
A body falls towards the earth. Does it have positive or negative acceleration?
Is it possible for an accelerating body to have constant speed?
Figure represents graphically the velocity of a car moving along a straight road over a period of 100 hours.
Calculate the acceleration along AB and the retardation along BC.
The acceleration of the body that moves with a uniform velocity will be ______.
What is meant by negative acceleration?
