Question

A cyclist driving at 5 ms^−1, picks a velocity of 10 ms⁻¹, over a distance of 50 m. Calculate

1. acceleration
2. time in which the cyclist picks up above velocity.

Answer 1

Initial velocity = u = 5 ms⁻¹
Final velocity = v = 10 ms⁻¹
Distance = S =50 m

(i) v² – u² = 2aS
(10)² – (5)² = 2a (50)
100 − 25 = 100a
100a = 75
a = `75/100` = 0.75 ms⁻²
∴ Acceleration = a = 0.75 ms⁻²

(ii) v = u + at
10 = 5 + 0.75t
0.75t = 10 − 5 = 5
(Time) t = `5/0.75` = 6.67 S