Advertisements
Advertisements
प्रश्न
A car traveling at 60 km/h, stops on applying brakes in 10 seconds. What is its acceleration?
Advertisements
उत्तर
First convert 60 km/h in m/s.
60 km/hr =(60 X 1000)/3600 = 16.7 m/s.
This is initial velocity of car i.e u = 16.7 m/s.
As car stops in 10 seconds so final velocity is =0 m/s.
So acceleration = (v-u)/t = (0-16.7)/10 = -1.67 ms-2.
Acceleration of car is = -1.67 ms-2.
APPEARS IN
संबंधित प्रश्न
Define the term acceleration due to gravity. State its average value.
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.

(a) Is the magnitude of acceleration higher or lower than that of retardation ? Give a reason .
(b) Compare the magnitude of acceleration and retardation .
A car travels with uniform velocity of 25 m s-1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find:
- The distance which the car travels before the brakes are applied,
- Retardation and
- The distance travelled by car after applying the brakes.
A motorbike, initially at rest, picks up a velocity of 72 kmh−1 over a distance of 40 m. Calculate
- acceleration
- time in which it picks up above velocity.
Define acceleration.
Out of energy and acceleration, which one is a vector?
Interpret the following graph:
A body has an acceleration of -3.5 ms-2. What is its retardation?
A car accelerates uniformly from a velocity of 18 km/h to 36 km/h in 15 min. What is its acceleration?
The speed of a particle is constant. Will it have acceleration? Justify with an example.
