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What is the coordination entity formed when excess of aqueous KCN is added to an aqueous solution of copper sulphate? Why is it that no precipitate of copper sulphide is obtained when H2S(g) is passed

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प्रश्न

What is the coordination entity formed when excess of aqueous KCN is added to an aqueous solution of copper sulphate? Why is it that no precipitate of copper sulphide is obtained when H2S(g) is passed through this solution?

विस्तार में उत्तर
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उत्तर

Under the given conditions, cupric cyanide is initially generated, which then decomposes to provide cuprous cyanide and cyanogen gas. Cuprous cyanide subsequently dissolves in an excess of potassium cyanide to provide the complex K3[Cu(CN)4].

\[\ce{CuSO4 + 2KCN -> Cu(CN)2 + K2SO4 \times 2}\]
\[\ce{2Cu(CN)2 -> Cu2(CN)2 + (CN)2}\]
\[\ce{Cu2(CN)2 + 6KCN -> 2K3[Cu(CN)4]}\]
_____________________________________________________
\[\ce{2CuSO4 + 10KCN -> 2K3[Cu(CN)4] + 2K2SO4 + (CN)2}\]

So, the coordination entity formed is [Cu(CN)4]3−.

The CN is a strong field ligand; the complex ion is highly stable and can’t dissociate to give copper ions. Hence, no precipitate of copper sulphide is formed when H2S(g) is passed through this solution.

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अध्याय 5: Coordinate Compounds - Exercises [पृष्ठ १३९]

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