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प्रश्न
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उत्तर
Structure of the given compounds are:

1) As we can see in the above figures, (A), contains the least steric hindrance so towards the SN2 reaction 1- bromopentane will be most reactive.
2) 2-bromopentane (Figure B) has chiral carbon in it. So, this compound is optically active.
3) Towards the β-elimination 2-bromo-2-methylbutane will be most reactive. Since it will form most stable alkene (on account of highest no. of α-hydrogens).
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संबंधित प्रश्न
Explain the following, giving two examples:
Coordination entity
What is meant by unidentate ligand?
Complete the following reactions
NH3+3Cl2(excess) ---->
Write the structures of compounds A, B and C in the following reactions

Write structures of compounds A and B of the following reaction :

Which of the following is non-ionizable?
Match the coordination compounds given in Column I with the central metal atoms given in Column II and assign the correct code:
| Column I (Coordination Compound) | Column II (Central metal atom) |
| A. Chlorophyll | 1. rhodium |
| B. Blood pigment | 2. cobalt |
| C. Wilkinson catalyst | 3. calcium |
| D. Vitamin B12 | 4. iron |
| 5. magnesium |
What is the relationship between observed colour of the complex and the wavelength of light absorbed by the complex?
How many ions are produced from the complex Co(NH3)6]Cl2 in solution?
The one that will show optical activity is: (en = ethane 1, 2-diamine)
