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प्रश्न
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उत्तर
Structure of the given compounds are:

1) As we can see in the above figures, (A), contains the least steric hindrance so towards the SN2 reaction 1- bromopentane will be most reactive.
2) 2-bromopentane (Figure B) has chiral carbon in it. So, this compound is optically active.
3) Towards the β-elimination 2-bromo-2-methylbutane will be most reactive. Since it will form most stable alkene (on account of highest no. of α-hydrogens).
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संबंधित प्रश्न
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