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Two Particles a and B, of Opposite Charges 2.0 × 10−6 C and −2.0 × 10−6 C, Are Placed at a Separation of 1.0 Cm. Calculate Electric Field at a Point on the Perpendicular Bisector of the Dipole and 1.0

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प्रश्न

Two particles A and B, of opposite charges 2.0 × 10−6 C and −2.0 × 10−6 C, are placed at a separation of 1.0 cm. Calculate the electric field at a point on the perpendicular bisector of the dipole and 1.0 m away from the centre. 

संख्यात्मक
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उत्तर

Given:
Magnitude of charge, q = 2.0 × 10−6 C
Separation between the charges, l = 1.0 cm 

Electric field at at a point on the perpendicular bisector of the dipole,

\[E = \frac{1}{4\pi \epsilon_0}\frac{P}{r '^3}\]
\[E = \frac{9 \times {10}^9 \times 2 \times {10}^{- 8}}{1^3}\]

E = 180 N/C 

 
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अध्याय 29: Electric Field and Potential - Exercises [पृष्ठ १२४]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 29 Electric Field and Potential
Exercises | Q 71.3 | पृष्ठ १२४

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