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Question
Two particles A and B, of opposite charges 2.0 × 10−6 C and −2.0 × 10−6 C, are placed at a separation of 1.0 cm. Calculate the electric field at a point on the perpendicular bisector of the dipole and 1.0 m away from the centre.
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Solution
Given:
Magnitude of charge, q = 2.0 × 10−6 C
Separation between the charges, l = 1.0 cm
Electric field at at a point on the perpendicular bisector of the dipole,
\[E = \frac{1}{4\pi \epsilon_0}\frac{P}{r '^3}\]
\[E = \frac{9 \times {10}^9 \times 2 \times {10}^{- 8}}{1^3}\]
E = 180 N/C
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