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Two cells of same emf E but internal resistance r1 and r2 are connected in series to an external resistor R (Figure). What should be the value of R so that the potential difference acros

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प्रश्न

Two cells of same emf E but internal resistance r1 and r2 are connected in series to an external resistor R (Figure). What should be the value of R so that the potential difference across the terminals of the first cell becomes zero.

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उत्तर

In this problem first we apply Ohm' law to find current in the circuit.

Effective  emf of two cells = E + E = 2E

Effective resistance = R + r1 + r2

So the electric current is given by

`I = (E + E)/(R + r_1 + r_2)`

`V_1 = E - Ir_1 = E - (2E.r_1)/(R + r_1 + r_2)`

The net potential difference across 1st cell V1 = 0 (Given)

∴ `E - (2Er_1)/(R + r_1 + r_2)` = 0

Or `1 - (2r_1)/(R + r_1 + r_2)` = 0

`(2r_1)/(r_1 + r_2 + R) = 1/1`

Or 2r1 = r1 + r2 + R

r1 – r2 = R

It is the required condition for the potential difference across 1st cell to be zero.

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अध्याय 3: Current Electricity - MCQ I [पृष्ठ २०]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 12
अध्याय 3 Current Electricity
MCQ I | Q 3.25 | पृष्ठ २०

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