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प्रश्न

Vinita and Ahmed demonstrated a circuit that operates the two headlights and the two sidelights of a car, in their school exhibition. Based on their demonstrated circuit, answer the following questions.
- State what happens when switch A is connected to:
a) Position 2
b) Position 3 - Find the potential difference across each lamp when lit.
- Calculate the current.
a) in each 12 Ω lamp when lit.
b) In each 4 Ω lamp when lit.
OR - Show, with calculations, which type of lamp, 4.0 Ω or 12 Ω, has the higher power.
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उत्तर
- (a) 12 Ω lamps (only) on.
(b) 4 Ω lamps (only) on. - 12 V for both sets of lamps and all of them are in parallel.
- a) 12 Ω lamps are on when the wire is connected to position 2.
The voltage across both 12 Ω lamps = 12 V.
V = IR (Ohm’s law)
`"I" = "V"/"R" = 12/12 = 1 "A"`
b) 4 Ω lamps are on when the wire is connected to position 3.
The voltage across both 4 Ω lamps = 12 V.
V = IR (Ohm’s law)
`"I" = "V"/"R" = 12/4 = 3 "A"`
OR - `"P" = "V"^2/"R"`
All lamps are in parallel and hence the same V for all lamps.
For 4 Ω lamps → P = `(12 xx 12)/4` = 36 W
For 12 Ω lamps → P = `(12 xx 12)/12` = 12 W
Hence 4 Ω lamps will have higher power.
APPEARS IN
संबंधित प्रश्न
Name the law which is illustrated by the above V−I graph.
Keeping the p.d. constant, the resistance of a circuit is halved. The current will become:
(a) one-fourth
(b) four time
(c) half
(d) double
State Ohm’s law and draw a neat labelled circuit diagram containing a battery, a key, a voltmeter, an ammeter, a rheostat and an unknown resistance to verify it.
What is meant by the drift speed of free electrons?
Ohm’s law states the relationship between power and voltage.
Define Current density.
How is electric current related to the potential difference across the terminals of a conductor?
Draw a labelled circuit diagram to verify this relationship.
